$\textbf{Pirates and Gold (II)}$
What will be the result if all are the same as # 4654 except that a proposal only requires $50\%$ of the vote to pass?
$\textbf{Answer}$
The first pirate can get $998$ pieces and the $3^{rd}$ and the $5^{th}$ will get one piece each.
$\textbf{Analysis}$
This problem can be solved using the same approach as # 4654.
Under this set of rules, if only two pirates left, then the $4^{th}$ will get all gold because his own vote suffices the $50\%$ majority.
Therefore, the $3^{rd}$ only need to offer the $5^{th}$ one piece to win his vote if there are three pirates left. In this case, the $4^{th}$ will get nothing.
It follows that the $2^{nd}$ only need to offer the $4^{th}$ one piece to win his vote. In this scenario, both the $3^{rd}$ and the $5^{th}$ will have nothing. This means that the first pirate only needs to offer them one piece each to get his proposal passed.