Problem - 3863
(Sophie Germain's Identity) Prove $a^4 + 4b^4 = (a^2+2b^2-2ab)(a^2+2b^2+2ab)$.
This identity can be easily proved by expanding the right side and then consolidating:
\begin{align}
&(a^2+2b^2-2ab)(a^2+2b^2+2ab)\\
&= (a^2+2b^2)^2-(2ab)^2\\
&= a^4 + 4b^4 - 4a^2b^2 - 4a^2b^2\\
&= a^4 + 4b^4
\end{align}