Problem - 4613
Compute $$\int\frac{x}{1+x^2}dx$$
$$\int\frac{x}{1+x^2}dx=\frac{1}{2}\int\frac{d(x^2)}{1+x^2}=\boxed{\frac{1}{2}\ln(1+x^2)+C}$$
Compute $$\int\frac{x}{1+x^2}dx$$
$$\int\frac{x}{1+x^2}dx=\frac{1}{2}\int\frac{d(x^2)}{1+x^2}=\boxed{\frac{1}{2}\ln(1+x^2)+C}$$