Integral Basic

Problem - 4610

Compute $$\int\frac{1}{ax+b}d{x}$$


This problem can be solved using the substitution method

$$\int\frac{1}{ax+b}d{x}=\frac{1}{a}\int\frac{1}{ax+b}d\left(ax+b\right)=\boxed{\frac{1}{a}\ln|{ax+b}|+C}$$

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