2013
Problem - 1807
A bag contains $8$ blue marbles, $4$ red marbles and $3$ green marbles. In a single draw, what is the probability of not drawing a green marble?
It is $\frac{8+4}{8+4+3}=\boxed{\frac{4}{5}}$.
It is $\frac{8+4}{8+4+3}=\boxed{\frac{4}{5}}$.