2012
Problem - 1184
How many $4$-digit numbers greater than $1000$ are there that use the four digits of $2012$?
When the thousands digit is $1$, there are $3$ possibilities because there are three choices for the digit $0$.
When the thousands digit is $2$, there are $3!$ possibilities.
Thus, the answer is $3+6=\boxed{9}$.